(v+3)^2=2v^2+10v-12

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Solution for (v+3)^2=2v^2+10v-12 equation: 



(v+3)^2=2v^2+10v-12

We move all terms to the left:

(v+3)^2-(2v^2+10v-12)=0

We get rid of parentheses

-2v^2+(v+3)^2-10v+12=0

We add all the numbers together, and all the variables

-2v^2-10v+(v+3)^2+12=0

We move all terms containing v to the left, all other terms to the right

-2v^2-10v+(v+3)^2=-12

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